The frequency of homozygous dominant individuals in this population is 0.55.
Explanation:
According to Hardy-Weinberg Equilibrium,
p + q = 1
For the Homozygous recessive gene is given by ².
where, p represents the frequency of dominant gene.
q represents the frequency of recessive gene.
² = 20 % = 20 / 100 = 0.2
q = [tex]\sqrt{0.2}[/tex]
q = 0.45
p + q = 1
p = 1 - q
= 1 - 0.45
p = 0.55.
