Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 9. Steve has a score of 52. Convert Steve's score to a z-score. (Round to two decimal places if necessary.)

a. 58.2
b. –1.33
c. 1.33
d. –2

Respuesta :

Answer:

b. –1.33

Step-by-step explanation:

The z-score measures how many standard deviations a score X is above or below the mean.

It is given by the following formula:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In which [tex]\mu[/tex] is the mean and [tex]\sigma[/tex] is the standard deviation.

In this problem, we have that:

[tex]\mu = 64, \sigma = 9, X = 52[/tex]. We have to find Z

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{52 - 64}{9}[/tex]

[tex]Z = -1.33[/tex]

So the correct answer is:

b. –1.33

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