The container of orange juice held 5 and one-third cups of juice. If a serving of orange juice is Start Fraction 7 Over 8 End Fraction of a cup of orange juice, to the nearest whole serving, how many servings were in the container?

Respuesta :

Answer:

Number of servings: [tex]6\frac{2}{21}[/tex]

Step-by-step explanation:

In this problem, we have a container of orange juice helding a total of

[tex]C=5\frac{1}{3}[/tex]

cups of juice.

We can re-write this mixed fraction as improper fraction, and we get:

[tex]C=\frac{5\cdot 3 +1}{3}=\frac{16}{3}[/tex]

We also know that a serving of orange juice is equal to

[tex]s=\frac{7}{8}[/tex]

of cup of orange juice.

Here we want to find how many servings are in the container: to find that, we have to divide the total amount of orange juice in the container (C) by the amount of juice per serving (s), so we find:

[tex]n=\frac{C}{s}=\frac{16/3}{7/8}=\frac{16}{3}\cdot \frac{8}{7}=\frac{128}{21}=6\frac{2}{21}[/tex]

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