Answer:
P=0.1238.
Step-by-step explanation:
We know that the Magazine Mass Marketing Company has received 14 entries in its latest sweepstakes. They know that the probability of receiving a magazine subscription order with an entry form is 0.4 .
We calculate the probability that no more than 3 of the entry forms will include an order.
We know that n=14, p=0.4 and q=0.6. We get
[tex]P(X=0)=C_0^{14}\cdot 0.4^0\cdot 0.6^{14}=0.00028\\\\P(X=1)=C_1^{14}\cdot 0.4^1\cdot 0.6^{13}=0.00731\\\\P(X=2)=C_2^{14}\cdot 0.4^2\cdot 0.6^{12}=0.03169\\\\P(X=3)=C_3^{14}\cdot 0.4^3\cdot 0.6^{11}=0.08451\\[/tex]
Therefore, the probability is
P=0.00028+0.00731+0.03169+0.08451
P=0.12379
P=0.1238.
