Answer:
d= 501.36 feet
t = 5.5 seconds
Step-by-step explanation:
Where U = Initial velocity, 55ft/s
d = ?
t= ?
From the solution diagram at Hmax the Final velocity of the rocket is zero. The equation of motion gives :
Hmax = U²/2g
= 55²/2 (10)
= 151.25ft
Using Pythagora's theorem:
d²= H²max +478²
= 151.25² + 478²
= 251,360.5625
d =√251,360.5625
= 501.3587
= 501.36 ft
The time t to reach Hmax is given by:
t = U/g
= 55/10
=5.5 seconds
