The final volume of water in container B is required.
The volume of water in container B will be [tex]3619.1\ \text{feet}^3[/tex].
r = Radius of cylinder
h = Height of cylinder
Container A
[tex]r_1=\dfrac{16}{2}=8\ \text{feet}[/tex]
[tex]h_1=18\ \text{feet}[/tex]
Container B
[tex]r_2=\dfrac{22}{2}=11\ \text{feet}[/tex]
[tex]h_2=15\ \text{feet}[/tex]
Volume of water in container A
[tex]V_1=\pi r_1^2h_1\\\Rightarrow V_1=\pi\times 8^2\times 18\\\Rightarrow V_1\approx 3619.1\ \text{feet}^3[/tex]
Since, container B is empty only the volume of container A will be present.
The volume of water in container B will be [tex]3619.1\ \text{feet}^3[/tex].
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