Answer:
1.81A
Explanation:
The magnitude of the magnetic force (F) acting on a current carrying wire is given by;
F = I x L x B sin θ ------------------(i)
Where;
I = current on the wire
B = magnetic strength
L = length of the wire
θ = angle between the wire and the magnetic field
From the question, there is a maximum force (F = 0.575N) of on the wire. This means that the angle between the wire and the magnetic field is 90°.
Also;
the magnetic field(B) = 0.0700-T
the length(L) of the wire = 4.55m
Substitute these values into equation (i) as follows;
0.575 = I x 4.55 x 0.0700 x sin 90°
0.575 = I x 4.55 x 0.0700 x 1
0.575 = I x 0.3185
Solve for I;
I = 0.575 / 0.3185
I = 1.81A
Therefore, the current flowing in the wire is 1.81A
