Answer:
a)
The magnitude of the attractive force is [tex]14.29N[/tex]
b)
The magnitude of the repulsive force is [tex]0.357N[/tex]
c)
The magnitude of the net force is [tex]0N[/tex]
Explanation:
The explanation is shown on the first and second uploaded image
The metal ball.
As per the question the tiny metal ball is arranged on a straight line and the central ball is positively charged and has two sides that are negatively charged. The outside ball is separated by 20 cm in middle is halfway in between.
Thus the answer to the magnitude is 14.29 N, the magnitude of the repulsive force is 0.35N and the net force is 0 North.
The metal ball is a at a distance of 20 cm an has an absolute value of change that is on each ball and is same as 1.12u.
The force of attraction has a magnitude of 14.2 due to the positively changed middle balls. The repulsive forced of either side of the ball are 0.35 north and net is 0 outside the ball.
Hence the change of the ball determines the direction.
Find out more information about the metal ball.
brainly.com/question/26368502.
