Answer:
[tex]x=0,y=2[/tex]
Step-by-step explanation:
Given equation:
[tex]2x + 4y = 8[/tex] Equation:1
[tex]x = 3y-6\\or\\x-3y=-6[/tex] Equation:2
Multiplying equation:2 by 2 gives:
[tex]2x-6y=-12[/tex] Equation:3
Subtracting Equation:3 from Equation:1
[tex]2x + 4y-(2x-6y) = 8-(-12)[/tex]
The negative sign outside the bracket changes the sign inside it after opening the bracket
[tex]2x+4y-2x+6y=8+12[/tex]
[tex]10y=20\\\\y=2[/tex]
Putting the value of 'y' in Equation:2
[tex]x-3y=-6\\x-3(2)=-6\\x-6=-6\\x=-6+6\\x=0[/tex]
[tex]x=0,y=2[/tex]
