Respuesta :
Answer:
3.52g
Explanation:
Zr = 90 g/mol
Si = 28 g/mol
O = 16 g/mol
ZrSiO4 = 90 + 28 + (16* 4) = 182g/mol
Mass = Numberof moles * Molar mass
Mass = 1mol * 182g/mol = 182g
In one mole of ZrSiO4, there are 4 oxygen atoms, hence the mass is given as;
4 * 16 = 64g
Hence, 64g of oxygen is present in 182g of ZrSiO4.
10g would contain x
64 = 182
x = 10
x = ( 10 * 64 ) / 182
x = 640 / 182 = 3.52g
The mass of oxygen present in 10 grams of Zircon is 3.5 grams.
Based on the given information,
• The empirical formula of Zircon is ZrSiO4.
• The molecular mass of zirconium is 90 g/mol, the molecular mass of silicon is 28 g/mol, and the molecular mass of oxygen is 16 g/mol.
Now the molar mass of ZrSiO4 is,
[tex]= (90+28+4*16) g/mol\\= 182 g/mol[/tex]
Now 1 mole of Zircon has 4 mole of oxygen, then 182 grams of Zircon will exhibit 4×16 grams of oxygen.
Now the mass of oxygen present in 10 grams of Zircon is,
[tex]= \frac{4*16g}{182 g} *10g[/tex]
[tex]= 3.5 g[/tex]
Thus, in 10 grams of Zircon, 3.5 grams of oxygen is present.
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