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A scientist mixes x liters of water into a container that has 10 liters of a mixture that is 12% salt and 88% water. The function f(x) = 1.2 / (x+10) represents the percent of the sat in the new mixture. How many liters of water must be added to make 1% salt mixture

Respuesta :

calculista

Answer:

110 liters of water

Step-by-step explanation:

Let

x ----> liters of water

f(x) ---->  the percent of the sat in the new mixture

we have

[tex]f(x)=\frac{1.2}{x+10}[/tex]

For [tex]f(x)=1\%=1/100=0.01[/tex]

substitute in the equation

[tex]0.01=\frac{1.2}{x+10}[/tex]

solve for x

[tex]x+10=\frac{1.2}{0.01}[/tex]

[tex]x+10=120\\x=120-10\\x=110\ L[/tex]

fichoh

Using the function given, the amount of water thst must be added to make 1% salt mixture is 110 litres.

The percentage of salt mixture is represented by the function :

  • [tex] f(x) = \frac{1.2}{x + 10}[/tex]

  • Percentage of salt mixture = f(x)

  • f(x) = 1% = 1/100 = 0.01

The equation can be expressed thus :

[tex] 0.01 = \frac{1.2}{x + 10}[/tex]

Cross multiply :

(x + 10)(0.01) = 1.2

0.01x + 0.1 = 1.2

0.01x = 1.2 - 0.1

0.01x = 1.1

x = 1.1 ÷ 0.01

x = 110

Hence, 110 litres of water must be added.

Learn more : https://brainly.com/question/14717218

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