Answer:
f₂ = 261.5Hz or 258.5Hz
Explanation:
The beat frequency = /f₁ - f₂/
where f₁ and f₂ are the frequencies of individua waves
f(beat) = 1.5Hz
f₁( frequency of one string) = 260Hz
f(beat) = /f₁ - f₂/
1.5Hz = /260Hz - f₂/
to solve this equation
we make it into two seprate equation and solve it separately
260Hz - f₂ = 1.5Hz
f₂ = 260Hz - 1.5Hz
= 258.5Hz
260Hz - f₂ = -1.5Hz
f₂ = 260Hz + 1.5Hz
= 261.5Hz
therefore, the two possible frequencies of the other strings are
f₂ = 258.5Hz or 261.5Hz
