Answer:
= 431.3 kPa
Explanation:
v = V/m = constant
Given that
T₁ = 100C
T₂ = 200C
V = 1m³
m = 2kg
initial volume = V/m
= 1/2
= 0.5m³kg⁻¹
from super heated water
T = 200 and P = 400kpa
specific volume = 0.53422m³kg⁻¹
from super heated water
where, T = 200 and P = 500kpa
specific volume = 0.42492m³kg⁻¹
we use method of linear interpolation to calculate our final pressure
P₂ = 400 + [tex]\frac{0.5 - 0.53422}{0.42492 - 0.53422} .(500 -400)[/tex]
= 431.3 kPa
