Answer: 5 years
14,800 students enrolled
Step-by-step explanation:
Let x represent the number of years and
Let y represent the number of students enrolled
College A: y = 12,300 + 500x
College B: y = 18,550 - 750x
Use substitution Method to solve:
12,300 + 500x = 18,550 - 750x
+750x +750x
12,300 + 1250x = 18,550
-12,300 -12,300
1250x = 6250
x = 5
Input x = 5 into one of the equations to solve for y.
y = 12,300 + 500x
= 12,300 + 500(5)
= 12,300 + 2500
= 14,800
Read more on Brainly.com - https://brainly.com/question/12387804#readmore
Answer: A. 2073
B. 79700
Step-by-step explanation:
Let x represent the number of years that it will take the two colleges to have the same enrollment.
In 2005 there were 11,700 students at college A, with a projected enrollment increase of 1000 students per year. This means that the total number of students that would be enrolled at college A in x years time would be
1000x + 11700
In the same year, there were 32,100 students at college B, with a projected enrollment decline of 700 students per year. This means that the total number of students that would be enrolled at college B in x years time would be
700x + 32100
For the two colleges to have the same enrollment, then
1000x + 11700 = 700x + 32100
1000x - 700x = 32100 - 11700
300x = 20400
x = 20400/300
x = 68
The year would be 2005 + 68 = 2073
B) The number of students that will be enrolled in the colleges is
1000 × 68 + 11700
= 79700
