Y=0.006x^3 -0.06x^2+1.4x, x is horizontal, and y is vertical, is it possible for the vertical distance of the helicopter to be there times the horizontal distance

Respuesta :

Answer:

  yes (at about (22, 66)

Step-by-step explanation:

If you subtract 3 times the horizontal distance, the equation becomes ...

  yv -yh = (0.006x^3 -0.06x^2+1.4x) -(3x) = 0.006x^3 -0.06x^2 -1.6x

The signs of the terms are +--, so Descartes' rule of signs tells us the one sign change indicates one positive real root. That is this difference will be zero for some positive value of x.

Yes, it is possible.

_____

The graph shows the condition will be met near x=22.

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