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A microwave oven running at 70 % efficiency delivers 950 W of energy per second to the interior. Part A Find the power drawn from the source. Express your answer using two significant figures.

Respuesta :

Answer:

[tex]P_i\approx1.4\times 10^3\ W[/tex]

Explanation:

Given:

  • power output of the oven, [tex]P_o=950\ W[/tex]
  • efficiency of the oven, [tex]\eta=70\%[/tex]

We know that the efficiency is given as:

[tex]\eta=\frac{P_o}{P_i}[/tex]

where:

[tex]P_i=[/tex] power taken from the source as input to the oven

[tex]0.7=\frac{950}{P_i}[/tex]

[tex]P_i=\frac{950}{0.7}[/tex]

[tex]P_i=1357.1429\ W[/tex]

[tex]P_i\approx1.4\times 10^3\ W[/tex]

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