Answer:
The number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.
Step-by-step explanation:
The box contains 13 computer chips. Of these 13 chips 3 are defective and 10 are good.
A quality control inspector samples 2 computer chips.
The number of ways to select at least 1 defective chip is:
n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)
The number of ways to select 1 defective chip is: [tex]{3\choose 1}{10\choose 1}=3\times10=30[/tex] ways.
The number of ways to select 2 defective chips is:[tex]{3\choose 2}{10\choose 0}=3\times1=3[/tex] ways.
n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)
= 30 + 3
= 33
Thus, the number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.
