Two blocks of mass 6 kg and 8 kg are connected by a string that runs over a massless pulley (or a frictionless peg). What is the magnitude of the acceleration after the blocks are released?

Respuesta :

Answer:

1.43

Explanation:

form two simultaneous equation and solved

The magnitude of the acceleration of each block is, a = 2.56 m/s²

The tension in the string is, T = 43.05 N

Given data,

The larger block of mass, M = 8.00 kg

The smaller block of mass, m = 6.00 kg

The formula for  At wood machine is,

                    Ma = Mg - T

                     ma = T - mg

Adding those equations,

                   a (M + m) = g ( M - m)

                       a = (M + m) / ( M - m)

Substituting the values,

                       a = (8 + 3.5) / (8 - 3.5)

                         = 2.56 m/s²

The magnitude of the acceleration of each block is, a = 2.56 m/s²

The tension in the string,

                      T = m(a + g)

                          = 3.5 ( 2.56 + 9.8)

                          = 43.05 N

The tension in the string is, T = 43.05 N

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