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1. A force of 60 Newtons is applied to the end of a wrench 0.12 m long. How much torque is produced?

Respuesta :

Answer:

7.2 N.m.

Explanation:

Torque is defined as the force and the distance in which it is acting.

Mathematically,

τ = d × F sin θ

Given:

Force = 60N

d = 0.12m

The force is applied at the end of the wrench, therefore it is applied at 90°.

τ = rF sin θ

= 0.12×60×sin90

= 0.12 × 60

= 7.2 N.m.

The quantity of torque that would be produced is 7.2 Nm

From the question,

We are to determine how much torque is produced

Torque is given by the formula

[tex]\tau = rFsin\theta[/tex]

Where [tex]\tau[/tex] is the torque

r is the radius

F is the force

and θ is the angle between F and the lever arm

From the given information,

F = 60 N

r = 0.12 m

Since the force was applied to the end of the wrench, then the force was applied perpendicularly

∴ θ = 90°

Putting the parameters into the formula,

We get

[tex]\tau = 0.12 \times 60 \sin90 ^{\circ}[/tex]

[tex]\tau = 0.12 \times 60 \times 1[/tex]

[tex]\tau = 7.2\ Nm[/tex]

Hence, the quantity of torque that would be produced is 7.2 Nm

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