Answer:
Volume of acid = 38.7 mL.
To neutralize 44 mL of NaOH
Explanation:
Formula for neutralization an acid and a base is:
M acid . Volume of acid = M base . Volume of base
Let's replace the data given:
0.1 M . Volume of acid = 8.80×10⁻² M . 44 mL
Volume of acid = (8.80×10⁻² M . 44 mL) / 0.1M → 38.7 mL
Answer:
We need 38.72 mL of the 0.100 M HClO4 solution
Explanation:
Step 1: Data given
Molarity of the HClO4 solution = 0.100 M
Volume of the 8.80 *10^-2 M NaOH solution = 44.00 mL
Step 2: Calculate the volume of HClO4
HClO4 + NaOH ⇒ NaClO4 + H2O
b*Ca*Va =a*Cb*Vb
⇒ with b = the coefficient of NaOH = 1
⇒ with Ca = the concentration of HClO4 = 0.100 M
⇒ with Va = The volume of HClO4 = TO BE DETERMINED
⇒ with a = the coefficient of HClO4 = 1
⇒ with Cb = the molarity of NaOH = 8.80 *10^-2 M
⇒ with Vb = the volume of NaOH = 44.00 mL = 0.044 L
1 * 0.100 * Va = 1 * 8.80*10^-2 *0.044
Va = 0.03872 L = 38.72 mL
We need 38.72 mL of the 0.100 M HClO4 solution
