Answer:
-98 K
Explanation:
Given
[tex]n=1/2=0.5\\W=570 J[/tex]
Given process is adiabatic and hence heat is zero. Thus change in internal energy is given by,
ΔU=Q-W
=0-570
=-570 J
Also for monoatomic gas change in internal energy is,
ΔU=3/2*n*R*ΔT
ΔT=-98
Since above answer has negative sign , which indicates temperature change is decrease.
Hence
The temperature change is approximately -98 K which is decrease.
