The estimated loader production is 527 ton/hour
The size of the bucket = 4cy
Assuming a conservative fill factor = 85% = 0.85
loaded weight = [tex]volume * unit weight[/tex]
loaded weight = [tex]0.35*4cy*300lb/cy=10540lb[/tex]
Generally, 4 cubic yards machine static dipping load is about 25,000lb.
Equating load [tex]=50[/tex]% of dipping load
[tex]50/100=x/25000=12500lb[/tex]
Since 12500lb > 10549lb which is the actual load and it is very okay.
Let the fixed cycle time be 30 sec/cycle.
Therefore, probably produce of loader [tex]=\frac{weight * efficiency factor}{cycle time}[/tex]
[tex]\frac{10540lb}{20lb/ton} * \frac{50}{60}*\frac{3600}{30}=527ton/hr[/tex]
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