Answer:
3. four
Explanation:
balanced equation:
∴ moles (n) S = 4 mol
∴ n O2 = 6 mol
limit reagent: S
⇒ mol SO3 = ( 4 mol S )*( 2 mol SO3 / 2 mol S )
⇒ n SO3 = 4 mol SO3
The moles of SO₃ that will be produced are:
3. four
2 S + 3 O₂ → 2 SO₃
Given:
Moles of S = 4 mol
Moles of O₂ = 6 mol
The limiting reagent in a chemical reaction is a reactant that is totally consumed when the chemical reaction is completed.
limit reagent: S
Moles of SO₃ = ( 4 mol S )*( 2 mol SO₃ / 2 mol S )
Moles of SO₃ = 4 mol SO₃
Thus, the moles of SO₃ that will be produced are: four moles
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