For the reaction ? S + ? O2 → ? SO3 , balance the equation. If four moles of sulfur (S) are combined with six moles of oxygen molecules (O2), how many moles of SO3 will be produced? 1. three 2. five 3. four 4. one 5. six 6. two 7. seven

Respuesta :

Answer:

3. four

Explanation:

balanced equation:

  • 2S + 3O2 → 2SO3

∴ moles (n) S = 4 mol

∴ n O2 = 6 mol

limit reagent: S

⇒ mol SO3 = ( 4 mol S )*( 2 mol SO3 / 2 mol S )

⇒ n SO3 = 4 mol SO3

The moles of SO₃ that will be produced are:

3. four

Balanced Chemical equation:

2 S + 3 O₂ → 2 SO₃

Given:

Moles of S = 4 mol

Moles of O₂ = 6 mol

The limiting reagent in a chemical reaction is a reactant that is totally consumed when the chemical reaction is completed.

limit reagent: S

Moles of  SO₃ = ( 4 mol S )*( 2 mol SO₃ / 2 mol S )

Moles of  SO₃ = 4 mol SO₃

Thus, the moles of SO₃ that will be produced are: four moles

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