Answer: 1393 K
Explanation:
To calculate the final temperature of the system, we use the equation given by Gay Lussac' s Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas.
[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas.
We are given:
[tex]P_1=3.85atm\\T_1=25^oC=(25+273)K=298K\\P_2=18.0atm\\T_2=?[/tex]
Putting values in above equation, we get:
[tex]\frac{3.85}{298K}=\frac{18.0}{T_2}\\\\T_2=1393K[/tex]
Thus 1393 K of temperature is required to raise the pressure to 18.0 atm.
