Respuesta :
Answer:
1.498 m
Explanation:
Electric potential due to a point charge V = K × Q / r
4.8 × 10 ⁴ V = 8.99 × 10⁹ N.m²/C² × 8 × 10⁻⁶ C / r
r = 8.99 × 10⁹ N.m²/C² × 8 × 10⁻⁶ C / 4.8 × 10 ⁴ V = 1.498 m
The distance of the electric potential from the point charge is 1.498 m.
What is electric potential?
Electric potential is the work done in moving a charge from one point to another in an electric field.
To calculate the distance of the electric potential from the point charge, we use the formula below.
Formula:
- V = kq/r............. Equation 1
Where:
- V = Electric potential
- k = coulomb's constant
- q = point charge
- r = distance.
Make r the subject of the equation
- r = kq/V.......... Equation 2
From the question,
Given:
- q = 8μC = 8×10⁻⁶ C
- k = 8.99×10⁹ Nm²/C²
- V = 4.8×10⁴ V
Substitute these values into equation 2
- r = [(8×10⁻⁶)(8.99×10⁹)]/(4.8×10⁴)
- r = 1.498 m
Hence, The distance of the electric potential from the point charge is 1.498 m.
Learn more about electric potential here: https://brainly.com/question/14883923