Respuesta :

Answer:

1.498 m

Explanation:

Electric potential due to a point charge V = K × Q / r

4.8 × 10 ⁴ V = 8.99 × 10⁹ N.m²/C² × 8 × 10⁻⁶ C / r

r = 8.99 × 10⁹ N.m²/C² × 8 × 10⁻⁶ C / 4.8 × 10 ⁴ V = 1.498 m

The distance of the electric potential from the point charge is 1.498 m.

What is electric potential?

Electric potential is the work done in moving a charge from one point to another in an electric field.

To calculate the distance of the electric potential from the point charge, we use the formula below.

Formula:

  • V = kq/r............. Equation 1

Where:

  • V = Electric potential
  • k = coulomb's constant
  • q = point charge
  • r = distance.

Make r the subject of the equation

  • r = kq/V.......... Equation 2

From the question,

Given:

  • q = 8μC = 8×10⁻⁶ C
  • k = 8.99×10⁹ Nm²/C²
  • V = 4.8×10⁴ V

Substitute these values into equation 2

  • r = [(8×10⁻⁶)(8.99×10⁹)]/(4.8×10⁴)
  • r = 1.498 m

Hence, The distance of the electric potential from the point charge is 1.498 m.

Learn more about electric potential here: https://brainly.com/question/14883923

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