A force of 16.88 n is applied tangentially to a wheel of radius 0.340 m and causes an angular acceleration of 1.20 rad/s2. What is the moment of inertia of the wheel?

Respuesta :

The moment of inertia will be "4.78 Kg-m²".

Given:

  • Force, F = 16.88 N
  • Radius, r = 0.34 m
  • Angular acceleration, α = 1.2 rad/s²

As we know,

→ [tex]F\times r = I\times \alpha[/tex]

or,

→       [tex]I = \frac{F\times r}{\alpha}[/tex]

By putting the values,

           [tex]= 4.78 \ Kg-m^2[/tex]

Thus the answer above is right.

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