Answer : The wavelength of photon is, [tex]4.63\times 10^{2}nm[/tex]
Explanation : Given,
Energy of photon = [tex]4.29\times 10^{-19}J[/tex]
Formula used :
[tex]E=h\times \nu[/tex]
As, [tex]\nu=\frac{c}{\lambda}[/tex]
So, [tex]E=h\times \frac{c}{\lambda}[/tex]
where,
[tex]\nu[/tex] = frequency of photon
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
[tex]\lambda[/tex] = wavelength of photon = ?
c = speed of light = [tex]3\times 10^8m/s[/tex]
Now put all the given values in the above formula, we get:
[tex]4.29\times 10^{-19}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}[/tex]
[tex]\lambda=4.63\times 10^{-7}m=4.63\times 10^{-7}\times 10^9nm=4.63\times 10^{2}nm[/tex]
Conversion used : [tex]1nm=10^{-9}m[/tex]
Therefore, the wavelength of photon is, [tex]4.63\times 10^{2}nm[/tex]
