A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 30 m/s and 40 m/s, respectively. 3. Approximately how long does it take the projectile to reach the highest point in its trajectory

Respuesta :

Answer:

The time is 5.10 sec.

Explanation:

Given that,

Component of velocity are 30 m/s and 40 m/s.

We need to calculate the resultant velocity

Using formula of resultant velocity

[tex]v=\sqrt{v_{x}^2+v_{y}^2}[/tex]

Put the value into the formula

[tex]v=\sqrt{(30)^2+(40)^2}[/tex]

[tex]v=50\ m/s[/tex][

We need to calculate the time

Using equation of motion

[tex]v = u+gt[/tex]

[tex]v = 0+gt[/tex]

[tex]t=\dfrac{v}{g}[/tex]

Put the value into the formula

[tex]t=\dfrac{50}{9.8}[/tex]

[tex]t=5.10\ sec[/tex]

Hence, The time is 5.10 sec.

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