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In a given lightning flash, the potential difference between a cloud and the ground is 2.86 times 109 V and the quantity of charge transferred is 23.1 C. What is the decrease in energy of the transferred charge? (Please give the magnitude.) If all that energy could be used to accelerate a 1519 kg automobile from rest, what would be the final speed of the automobile?

Respuesta :

Answer:

Explanation:

decrease in energy of the transferred charge

= Voltage x charge

= 2.86 x 10⁹ x 23.1

= 66.067 x 10⁹ J

the final speed of the automobile be V

1/2 m v² = 66.067 x 10⁹

v² = 66.067 x 10⁹ x 2 / 1519

= .08698 x10⁹

= 87 x 10⁶

v = 9.32 x 10³ m / s

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