Answer:
a
a.) The total charge can be treated as a point charge as if the sphere were compacted to a point (by Gauss's law).The magnitude of the charge can be found by the electric field equation
Electric Field due to a point charge at a distance is
[tex]E =\frac{kq}{r^{2}}[/tex]
Here, q is charge so
[tex]q = \frac{Er{2}}{k}[/tex]
[tex]= \frac{(890N/C)(0.75m)^{2}}{(9*10^{9}Nm^{2}/C^{2})}[/tex]
[tex]= 55.62*10^{-9}[/tex]
[tex]=55.62nC[/tex]
So the charge on the surface would be [tex]=55.62nC[/tex]
b
The charge on the interior surface is equal to -Q(i.e [tex]-55.62nC[/tex] ), since the net charge is zero.It is also distributed uniformly.
c
The charge on the inside is equal to Q, inducing the charge on the inside of the shell, which in turn induces the charge on the outside. We can't say exactly how it is distributed due to Gauss's law, but we at least know it is symmetric since the field is uniform.
Explanation:
In order to get a better understanding of the solution above let get to know more about the Gauss's law
Gauss's law
This law talks about the distribution of the electric that produces the electric field
This law states that the the net flux of an electric field through a closed surface is proportional to the enclosed enveloped electric charge and we can say that an electric flux is the product of a given area and the electric field passing through this area.
