A surfboard shaper has to limit the cost of development and production to ​$ 215 per surfboard. He has already spent ​$ 30,240 on equipment for the boards. The development and production costs are ​$ 143 per board. The cost per board is 143x+30,240/x dollars. Determine the number of boards that must be sold to limit the final cost per board to $ 215.

Respuesta :

Answer:

420 boards.

Step-by-step explanation:

We have been given the formula for cost per board as [tex]\frac{143x+30240}{x}[/tex], where x represent number of boards. We are asked to find the number of boards that must be sold to limit the final cost per board to $215.

To find the number of boards, we will equate cost of x boards by 215 and solve for x as shown below:

[tex]\frac{143x+30240}{x}=215[/tex]

[tex]\frac{143x+30240}{x}*x=215*x[/tex]

[tex]143x+30240=215x[/tex]

[tex]143x-143x+30240=215x-143x[/tex]

[tex]30240=72x[/tex]

[tex]72x=30240[/tex]

[tex]\frac{72x}{72}=\frac{30240}{72}[/tex]

[tex]x=420[/tex]

Therefore, 420 boards must be sold to limit the final cost per board to $215.

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