Answer:
The midpoint of both diagonals is (4 and one-half, 5 and one-half), the slope of RP is 7, and the slope of SQ is Negative one-sevenths.
Step-by-step explanation:
For a square PQRS, the diagonals will be RP and SQ.
We know the diagonals of a square bisect each other.
To show that the diagonals are perpendicular, then the product of their slope must be -1.
We have that the slope of
[tex]RP = 7[/tex]
and the slope of
[tex]SQ = - \frac{1}{7} [/tex]
Their product is:
[tex]7 \times - \frac{1}{7} = - 1[/tex]
