(1) acceleration, a = 4 m/[tex]s^{2}[/tex] (2) acceleration of 10 N, [tex]a_{1}[/tex] = 1 m/[tex]s^{2}[/tex] and acceleration of 30 N, [tex]a_{2}[/tex] = 3 m/[tex]s^{2}[/tex]
Explanation:
- Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object.
- Let [tex]a_{1}[/tex] be the acceleration for force 10 N, to find acceleration rearrange the equation to a = [tex]\frac{F}{m}[/tex]. When we substitute 10 N force and 10 kg mass of the box in the equation. We will get [tex]a_{1}[/tex] = 1 m/[tex]s^{2}[/tex]
- Let [tex]a_{2}[/tex] be the acceleration for force 30 N, to find acceleration rearrange the equation to F = [tex]\frac{F}{m}[/tex]. When we substitute 30 N force and 10 kg mass of the box in the equation. We will get [tex]a_{2}[/tex] = 3 m/[tex]s^{2}[/tex]
- To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/[tex]s^{2}[/tex]
