Electric charge is uniformly distributed inside a nonconducting sphere of radius 0.30m. the electric field at a point p, which is 0.50m from the center of the sphere, is 17,000 N/C and is directed radially outward. What is the maximum magnitude of the electric field due to this sphere?

A) 25,000 N/C

B) 42,000 N/C

C) 36,000 N/C

D) 47,000 N/C

E) 30,000 N/C

Respuesta :

Answer:

The maximum magnitude of the electric field due to this sphere is 47200 N/C.

This value is near by option D.

Explanation:

Given that,

Radius of the sphere R= 0.30 m

Distance from the center of the sphere r= 0.50 m

Electric field = 17000 N/C

r > R and for this value of r,

We need to calculate the charge

Using formula of electric field

[tex]E=\dfrac{kQ}{r^2}[/tex]

[tex]Q=\dfrac{Er^2}{k}[/tex]

Put the value into the formula

[tex]Q=\dfrac{17000\times(0.50)^2}{9\times10^{9}}[/tex]

[tex]Q=4.72\times10^{-7}\ C[/tex]

The charge is positive as the field direction is radially outward.

For a non conducting sphere of radius R,

We need to calculate the maximum magnitude of the electric field due to this sphere

Using formula of electric field

[tex]E_{max}=\dfrac{kQ}{r^2}[/tex]

Put the value into the formula

[tex]E_{max}=\dfrac{9\times10^{9}\times4.72\times10^{-7}}{0.3^2}[/tex]

[tex]E_{max}=47200\ N/C[/tex]

Hence, The maximum magnitude of the electric field due to this sphere is 47200 N/C.

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE