Answer:
Explanation:
The charge on the electron is
q=1.6×10^-19C
It moves in a path perpendicular to the electric field
Given that the uniform electric field is
E=3N/C.
We need to calculate Work
Distance moved is
d=15cm=0.15m
W=q ∫E.ds
Thus, the angle θ between the path and electric field is 90°, and the dot product E.ds is zero
E.ds= Eds Cos θ= Edscos90
Cos 90=0
Then E.ds=0
Now,
W=q ∫E.ds
W=q × 0
W=0J
