Answer:
$19,250 is the difference in total cost between Apartment "A" and Apartment "B".
Step-by-step explanation:
Apartment A
Length of first floor = l = 40 ft
Width of the first floor = w = 30 ft
Area of first floors = A = lw = [tex]40ft\times 30 ft=1200 ft^2[/tex]
Area of first floors = Area of second floor = [tex]1200 ft^2[/tex]
Length of third floor = l' = 15 ft
Width of the third floor = w' = 30 ft
Area of third floors = A' = l'w' = [tex]15 ft\times 30 ft=450 ft^2[/tex]
Total area of the floor of apartment A = T
T = A +A +A' = [tex]1200 ft^2+1200ft^2+450 ft^2=2850 ft^2[/tex]
The cost of floor = $55 per square foot
Total Cost of apartment A :
C = [tex]55 \$/ft \times 2850 ft^2 =\$156,750[/tex]
Apartment B
Length of first floor = L = 40 ft
Width of the first floor = W = 40 ft
Area of first floors = a = LW = [tex]40ft\times 40 ft=1600 ft^2[/tex]
Area of first floors = Area of second floor = [tex]1600 ft^2[/tex]
Total area of the floor of apartment B = T'
T' = a + a = [tex]1600 ft^2+1600ft^2=3200 ft^2[/tex]
The cost of floor = $55 per square foot
Total Cost of apartment B :
C' = [tex]55 \$/ft \times 3200 ft^2 =\$176,000[/tex]
The difference in total cost between Apartment "A" and Apartment "B"L:
C' - C = $176,000 - $156,750 = $19,250
$19,250 is the difference in total cost between Apartment "A" and Apartment "B".
