Option C:
Diagonals of a rhombus bisect each other is the best statement to the given equation.
Solution:
Given CAMP is a rhombus.
PQ = x + 2 and QA = 3x – 14
Given equation is x + 2 = 3x – 14.
To find which statement is true for the equation:
Option A: All four sides of a rhombus are congruent.
This means CA = AM = MP = PC.
It is not relevant to the given equation.
Option B: Diagonals of a rhombus are perpendicular.
This means the angle formed in the intersection of the diagonals are 90°.
It is not relevant to the given equation.
Option C: Diagonals of a rhombus bisect each other.
This means PQ = QA and CQ = QM
This is the best statement explains why the equation is x + 2 = 3x – 14.
x + 2 = 3x – 14
2x = 16
x = 8
Option D: Opposite sides of a rhombus are parallel.
This means PM = CA.
It is not relevant to the given equation.
Hence Option C, diagonals of a rhombus bisect each other is the best statement to the given equation.
