If a rock is thrown upward on the planet Mars with a velocity of 17 m/s, its height (in meters) after t seconds is given by H = 17t − 1.86t2.(a) Find the velocity of the rock after two seconds.9.6 Correct: Your answer is correct. m/s(b) Find the velocity of the rock when t = a. Correct: Your answer is correct. m/s(c) When will the rock hit the surface? (Round your answer to one decimal place.

Respuesta :

Answer:

(a) 9.6

(b) [tex]17 - 3.72a[/tex]

(c) 9.1 s

Explanation:

Velocity is the time-derivative of position. From the question,

[tex]H = 17t − 1.86t^2[/tex]

[tex]v(t) = \dfrac{d}{dt}H = 17-3.72t[/tex]

(a) When [tex]t=2[/tex]

[tex]v(t) = 17-3.72\times2 = 17 - 7.44 = 9.56 = 9.6 \text { to 1 decimal place}[/tex]

(b) When [tex]t=a[/tex]

[tex]v(a) = 17-3.72a[/tex]

(c) The rock will hit the surface when When [tex]H=0[/tex].

[tex]H = 17t − 1.86t^2 = 0[/tex]

[tex]t(17 − 1.86t) = 0[/tex]

[tex]t = 0[/tex] (This is when the rock was thrown)

or

[tex]17 − 1.86t = 0[/tex]

[tex]17 = 1.86t[/tex]

[tex]t = \dfrac{17}{1.86} = 9.1398 = 9.1\text { to 1 decimal place}[/tex]

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