At time t=3, there are 2.5 cubic feet of water in the tub. Write an equation for the locally linear approximation of W at t=3, and use it to approximate the volume of water in the tub at time t=3.5

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lucic

Answer:

W=0.8333*t

2.917 ft³

Step-by-step explanation:

At time t=3, there is 2.5 ft³ of water in the tub

Finding the relation will be;

3=2.5

1=?

Rate=0.8333 ft³/min

W=0.8333 ft³ / min

W=0.8333*t

At t=3.5 will be;

1 min = 0.8333

3.5 min =?

Apply cross-production

3.5*0.8333 =2.917 ft³

aksnkj

The linear expression representing the volume of water in the tub is [tex]W=0.833t[/tex] and the volume of water after 3.5 minutes will be [tex]2.916\rm\; ft^3[/tex].

Given information:

At time t=3, there are 2.5 cubic feet of water in the tub.

Let the time be in minutes.

So, the rate of flowing the water in the tub will be,

[tex]r=\dfrac{2.5\rm\; ft^3}{3\; \rm min}\\r=0.833 \rm\; ft^3/min[/tex]

So, the expression for volume of water W in the tub will be,

[tex]W=rt\\W=0.833\times t[/tex]

Above is the expression for water in the tub at t minutes.

Now, the water in the tub after 3.5 minutes will be,

[tex]W=0.833\times t\\W(3.5)=0.833\times 3.5\\W=2.916\rm\; ft^3[/tex]

Therefore, the linear expression representing the volume of water in the tub is [tex]W=0.833t[/tex] and the volume of water after 3.5 minutes will be [tex]2.916\rm\; ft^3[/tex].

For more details, refer to the link:

https://brainly.com/question/23113065

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