Answer: [tex]142.5\ ft^2[/tex]
Step-by-step explanation:
The figure is attached (which is based on the description given)
Notice that you can divide it into two figures: a rectangle and a triangle.
The area of a rectangle can be found with this formula:
[tex]A_r=lw[/tex]
Where "l" is the length and "w" is the width.
In this case:
[tex]l=15\ ft\\w=7\ ft[/tex]
Therefore, the area of the rectangle is:
[tex]A_r=(15\ ft)(7\ ft)\\\\A_r=105\ ft^2[/tex]
The area of a triangle can be calculated with the following formula:
[tex]A_t=\frac{bh}{2}[/tex]
Where "b" is the base and "h" is the height.
In this case, you can identify that:
[tex]b=15\ ft\\h=12\ ft-7\ ft=5\ ft[/tex]
Therefore, substituting values and evaluating, you get:
[tex]A_t=\frac{(15\ ft)(5\ ft)}{2}\\\\A_t=37.5\ ft^2[/tex]
Finally, you must add the areas calculated above, in order to find the area of the wall. This is:
[tex]A_w=105\ ft^2+37.5\ ft^2\\\\A_w=142.5\ ft^2[/tex]
