Respuesta :
Answer:
t = 11.83 s
It will take 11.83 seconds
Step-by-step explanation:
The distance covered can be derived using the equation of motion with no acceleration.
distance d = speed v × time t
d = vt
For the first automobile,
v = 55km/h
d1 = 55t ....1
For the second automobile,
v = 20km/h
Initial distance d0 = 115m = 0.115km
d = vt + d0
d2 = 20t + 0.115 ......2
For them to meet/overtake each other,
Their distance at that time must be equal.
d1 = d2
55t = 20t + 0.115
55t-20t = 0.115
35t = 0.115
t = 0.115/35 hr
Converting to seconds
t = 0.115/35 × 3600s
t = 11.83 s
Answer:
It takes 11.83 s.
Step-by-step explanation:
If two objects move in the same direction at different speeds their relative speed = Fastest speed – slowest speed.
The time after which the two objects meet is given by
[tex]t=\frac{distance}{relative \:speed}[/tex]
We know that an car traveling in the left lane of a highway has a speed of 55.0 km/h and the other car has a speed of 20.0 km/h.
The initial distance between them was 115 m, which is equivalent to [tex]115 \:m\cdot (\frac{1\:km}{1000\:m} )=0.115\:km[/tex] .
The relative speed is
[tex]55.0\:\frac{km}{h} -20.0\:\frac{km}{h}=35\:\frac{km}{h}[/tex]
and the time when the two cars meet is
[tex]\frac{0.115 \:km}{35\:\frac{km}{h} } \approx0.003286 \:h[/tex] or [tex]0.003286 \:h\cdot (\frac{3600}{1\:h} )=11.83 \:s[/tex]
