An object starts from rest and accelerates uniformly in a straight line in the positive x direction. After 11 seconds, its speed is 70.0 m/s. What is the average velocity of the object during the first 11 seconds?

To calculate the average velocity we must know the distance traveled and do [tex]v_{avg}=\frac{d}{t}[/tex]. The distance traveled is [tex]d=\frac{at^2}{2}[/tex], so we need to calculate the acceleration, which, since it's uniform, is [tex]a=\frac{\Delta v}{\Delta t}=\frac{v_f}{t}[/tex]. Putting all together:

[tex]v_{avg}=\frac{d}{t}=\frac{at^2}{2t}=\frac{at}{2}=\frac{v_ft}{2t}=\frac{v_f}{2}=35m/s[/tex]

onyebuchinnaji onyebuchinnaji · Answer 2 · 2021-10-26T17:45:49+02:00

The average velocity of the object during the motion is 70 m/s.

The given parameters;

initial velocity of the object, u = o
final velocity of the object, v = 70 m/s
time of motion, t = 11 seconds

The initial displacement of the object is calculated as follows;

s₀ = ut

s₀ = 0

The displacement of the object after first 11 second is calculated as follows;

s₁ = vt

s₁ = 70 x 11 = 770 m

The average velocity of the object is calculated as follows;

[tex]v = \frac{s_1 - s_0}{t} \\\\v = \frac{770 - 0}{11} \\\\v = 70 \ m/s[/tex]

Thus, the average velocity of the object is 70 m/s.

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