Arrange the following 0.10 MM solutions in order of increasing acidity: (i) NH4NO3NH4NO3, (ii) NaNO3NaNO3, (iii) CH3COONH4CH3COONH4, (iv) NaFNaF, (v) CH3COONa

Respuesta :

Answer:

The answer to the question is

In order of increasing acidity, we have

CH3COONa→NaF→NaNO3→CH3COONH4→NH4NO3

Explanation:

(i) NH4NO3 is an acidic salt as it consists of NH₃ and HNO₃. NH₃ is a weak base and  HNO₃ is a strong acid pH = 5.4

(ii) NaNO3  PH7 produces a neutral solution when dissolved in water

(iii) CH3COONH4 Very concentrated solutions are acidic while low concentration 0.5 M are neutral, pH = 7

(iv) NaF basic as it is formed from  weak acid and  strong base. The strength of the basicity depends on the solution pH 7.4

(v) CH3COONa Basic in small concentration pH  8 or 9

Therefore we have in order of increasing acidity, CH3COONa→NaF→NaNO3→CH3COONH4→NH4NO3

The order increasing acidity of the solutions is; CH3COONa ≈ NaF < CH3COONH4 < NH4NO3.

An acidic solution is one whose pH lies between 0 to 6. A salt that undergoes hydrolysis to give an acid will have an acidic pH. Let us now consider the solutions to know which of them will give an acid solution.

  • The salt NH4NO3 will give an acid solution because its hydrolysis yields nitric acid
  • The salt  CH3COONH4 yields a neutral solution
  • The salt NaF yields a basic solution because its hydrolysis yields NaOH.
  • The salt CH3COONa yields a basic solution since its hydrolysis yields NaOH.

The order increasing acidity of the solutions is; CH3COONa ≈ NaF < CH3COONH4 < NH4NO3.

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