Answer:
Density of solution = 1.43 g/mL
Molality → mol/kg = 37 m
Explanation:
The solute is HNO₃
Molar mass → 63 g/mol
70 % by mass → 70 g of solute / 100 g of solution
We convert the mass of HNO₃ to moles → 70 g / 63 g/mol = 1.11 moles
So let's apply molarity to find out the volume of our moles.
Molarity (M) = mol/L → mol / M = L → 1.11 mol / 15.9 M = 0.070 L
This is the volume for solution. We can convert it from L to mL
0.070 L . 1000 mL / 1L = 70 mL
As the mass of solution = 100 g → Density = Mass/Volume
100g / 70 mL = 1.43 g/mL
Molality → mol of solute / kg of solvent
Solution mass = 100 g → Mass of solute + Mass of solvent
Mass of solvent = 30 g
We convert the mass of solvent from g to kg → 30 g . 1kg / 1000 g = 0.030 kg
Molality (mol/kg) → 1.11 mol / 0.030 kg = 37 m
The density of the solution has been 1.43 g/ml. The molality of the solution has been 37.03 m.
Density can be defined as the mass of the solution per unit of volume. The density can be calculated as:
[tex]D=\rm\dfrac{m}{v}[/tex]
Where, D has been the density.
The molecular weight of nitric acid has been, [tex]mwt=63.013\;\rm g/mol[/tex]
The mass of nitric acid has been, [tex]m=70\;g[/tex]
The molarity of the solution has been given as, [tex]M=15.9\;\rm mol/L[/tex]
The volume of the solution can be given as:
[tex]\rm V=Molarity\;\times\;\dfrac{molecular\;mass}{mass}\\V=15.9\;\times\;\dfrac{70}{63.013} \;L\\V=0.070\;L[/tex]
Substituting the values for density,
[tex]D=\dfrac{100}{70}\;\rm {g/ml}\\D= 1.43\;\rm g/ml[/tex]
The density of the solution has been 1.43 g/ml.
The molality of the solution has been given by :
[tex]m=\dfrac{M}{m_S}[/tex]
Where, moles of the solute has been given as, [tex]M=\rm 1.11\;mol[/tex]
The mass of the solvent has been given as, [tex]m_s=0.030\;\rm kg[/tex]
Substituting the values for calculating molality, m:
[tex]m=\rm \dfrac{1.11\;mol}{0.030\;kg} \\\textit m = 37.03\;m[/tex]
The molality of the solution has been 37.03 m.
For more information about the molality, refer to the link:
https://brainly.com/question/4580605
