contestada

A gas occupies 900.0 mL at a temperature of 27.0 ˚C. Assuming constant pressure, what is its volume if it is heated to 132.0 ˚C?

Respuesta :

Answer:

new volume is 1215mL

Explanation:

using Charles law , the volume of a fixed mass of gas is directly proportional to its temperature provide that pressure is kept constant.

[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]

V1=900mL ,

convert the temperatures from Celsius to kelvin temperature.

T1 =27°C =27+273 =300K

T2 =132°C = 132+273=405K

[tex]V2=\frac{V1T2}{T1}[/tex]

[tex]V2=\frac{900*405}{300}[/tex]

V2= 1215mL

Answer:

V₁ = 900.0 mL

T₁ = 27.0ºC + 273 = 300 K

V₂ = ?

T₂ = 132.0 + 273 = 405 K

V₁ / T₁ = V₂ / T₂

900.0 / 300 = V₂ / 405

300 x V₂ = 405 x 900.0

300 x V₂ = 364500

V₂ = 364500 / 300

V₂ = 1215 mL

Explanation:

hope this helps mate

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