Answer:
9.8 m/s
Explanation:
A freely falling object is under the influence of gravity. And the gravitational acceleration of Earth is -9.8 m/s2. Here, the negative sign indicates that the acceleration vector is towards the ground.
Therefore, the object gains 9.8 m/s each second.
Applying the equation of kinematics will show the velocity of the object.
[tex]v_y = v_{0_y} + a_y t\\v_y = v_{0_y} - 9.8t[/tex]
At t = 0:
[tex]v_y = v_{0_y}[/tex]
At t = 1:
[tex]v_y = v_{0_y} - 9.8[/tex]
At t = 2:
[tex]v_y = v_{0_y} - 2(9.8)[/tex]
Therefore, the speed of the object would increase 9.8 m/s each second until it hits the ground.
