Answer: 5.14 moles
Explanation:
heat supplied: 8280 J
The formula used for heat absorbed by an ideal gas:
[tex]q=n\times C_v\times (T_2-T_1)[/tex]
where,
q = heat absorbed = 8280 J
[tex]C_v[/tex] = for monoatomic gas = [tex]\frac{3}{2}R[/tex]
n = number of moles
R = gas constant = 8.314 J/Kmol
[tex]T_1[/tex] = initial temperature = 206 K
[tex]T_2[/tex] = final temperature = 335 K
Now put all the given values in the above formula,
[tex]8280J=n\times \frac{3}{2}\times (8.314J/Kmol)\times (335-206)K[/tex]
[tex]n=5.14[/tex]
Thus there are 5.14 moles of gas in the container.
