contestada

Given that events A and B are mutually exclusive, i.e., A?B = ? and P(A?B) =0, and that P(A)=0.7 and P(B)=0.2, find P(A or B).

(a) 0.14

(b) 0.9

(c) 0.5

(d) 0.76

(e)1.04

Respuesta :

Answer:

[tex]P(A or B)= P(A \cup B) = 0.9[/tex]

Step-by-step explanation:

given ,      [tex]P(A)=0.7[/tex]    [tex]P(B)=0.2[/tex]

                   [tex]P(A or B) = P(A \cup B) =0[/tex]

since it is mutually exclusive event ,  [tex]P(A and B)= P(A \cap B) =P(A?B) = 0[/tex]

           [tex]P(A \cup B) = P(A) + P(B) - P(A\cap B)[/tex]

            [tex]P(A \cup B) = 0.7 + 0.2 - 0[/tex]

            [tex]P(A \cup B) = 0.9[/tex]

   

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas