Answer:
Keq=0.866
Explanation:
Hello,
In this case, the undergone chemical reaction is:
[tex]N_2O_4<->2NO_2[/tex]
In such a way, since 0.0055 mol of N₂O₄ remains in the flask, one infers that the reacted amount ([tex]x[/tex]) was:
[tex]x=0.04mol-0.0055mol=0.0345mol[/tex]
In addition, the produced amount of NO₂ is:
[tex]2*0.0345mol=0.069mol[/tex]
Finally, considering the flask's volume, the equilibrium constant is then computed as follows:
[tex]Keq=\frac{(2*0.0345M)^2}{0.0055M}=0.866[/tex]
Best regards.
