Respuesta :
Answer:
82.5 J
Explanation:
Energy stored on a capacitor = CV²/2
But Q = CV
Energy = QV/2
Q = 15.0 mC = 0.015 C
V = 11 × 10³ V = 11000 V
Energy = 0.015 × 11000/2 = 82.5 J
Therefore, the energy stored on a capacitor which has stored charge of 15.0 mC (on each plate, opposite signs for each) and a voltage of 11e3 V is 82.5 J
Answer:
U = 82.5 J
The energy stored on the capacitor is 82.5J
Explanation:
The energy stored in a capacitor U can be expressed as;
U = 0.5CV^2 = Q^2/2C = QV/2
Where,
C = capacitance
V = potential difference
Q = charge on the plates
Given;
Q = 15 mC = 15×10^-3 C
V = 11e3V = 11×10^3 V
From;
U = QV/2
U = 15×10^-3 C × 11×10^3 V / 2
U = 82.5 J
The energy stored on the capacitor is 82.5J
